1589C - Two Arrays - CodeForces Solution

greedy math sortings *900

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Python Code: 

t = int(input())

for _ in range(t):
    n = int(input())
    a = list(map(int,input().split()))
    b = list(map(int,input().split()))
    
    a.sort()
    b.sort()
    ans = "YES"
    for i in range(n):
        if a[i] != b[i] and a[i] + 1 != b[i]:
            ans = "NO"
            break
            
    print(ans)

C++ Code: 

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int i, t;
    cin >> t;

    for (i = 0; i < t; i++)
    {
        int a, b, j, n, flag = 0;
        cin >> n;
        vector<int> A(n);
        vector<int> B(n);

        for (j = 0; j < n; j++)
        {
            cin >> a;
            A[j] = a;
        }
        sort(A.begin(), A.end());

        for (j = 0; j < n; j++)
        {
            cin >> b;
            B[j] = b;
        }
        sort(B.begin(), B.end());

        for (j = 0; j < n; j++)
        {
            if ((B[j] - A[j] != 0) && (B[j] - A[j] != 1))
            {
                flag = 1;
                break;
            }
        }

        if (flag == 1)
            cout << "NO" << endl;
        else
            cout << "YES" << endl;
    }

    return 0;
}


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